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AD is a median of $\triangle ABC$ with vertices $A(5, - 6)$, $B(6, 4)$ and $C(0, 0)$. Length AD is equal to :
- (a)$\sqrt{68}$ units
- (b)$2\sqrt{15}$ units
- (c)$\sqrt{101}$ units
- (d)$10$ units
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(a) $\sqrt{68}$ units
CBSE Class 10 Maths PYQ · Coordinate Geometry · Application · 1 Mark · March 2024 · Standard
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