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PT is tangent to the circle with centre O and radius 5 cm. OP intersects the circle at Q. If PQ = $x$, then $PT^2$ equals :
- (a)$x^2 + 5x$
- (b)$x^2+10x$
- (c)$x^2+10x + 50$
- (d)$x^2-25$
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Answer: (C) $x^2 + 10x$
PT is tangent to the circle with centre O and radius 5 cm. OP intersects the circle at Q. If PQ = x , then PT2 equals :
CBSE Class 10 Maths PYQ · Circles · Tangents & All · 1 Mark · March 2026 · Basic
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