85
$PA$ and $PB$ are tangents to a circle with centre $O$. If $\angle AOB = 105^\circ$ then $\angle OAP + \angle APB$ is equal to :
- (a)$75^\circ$
- (b)$175^\circ$
- (c)$180^\circ$
- (d)$165^\circ$
Show SolutionHide Solution↓
Ans. (d) $165^\circ$
PA and PB are tangents to a circle with centre O . If ∠ AOB = 105° then ∠ OAP + ∠ APB is equal to :
CBSE Class 10 Maths PYQ · Circles · Find angles · 1 Mark · March 2025 · Basic
Solve it yourself first — then press ↓ or tap Show Solution. Use ← → for previous / next question.