OR In the given figure, tangents PQ and PR are drawn to a circle such that ∠ RPQ = 30° . A chord RS is drawn parallel…

$PQ = PR$ (tangents drawn from an external point to the circle)
$\therefore \angle PQR = \angle PRQ$
In $\triangle PQR$, $\angle PQR = \angle PRQ = \frac{1}{2}(180^{\circ} - 30^{\circ}) = 75^{\circ}$
Draw a perpendicular QL from Q to QP
Now, $\angle PQL = 90^{\circ}$
$\therefore \angle RQL = 90^{\circ} - 75^{\circ} = 15^{\circ}$
$\triangle RQL \cong \triangle SQL$ (SAS )
$\therefore \angle RQL = \angle SQL = 15^{\circ}$
$\therefore \angle RQS = 15^{\circ} +15^{\circ} = 30^{\circ}$