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In the given figure, TP is tangent to a circle with centre O. Diameter BA when produced meets the tangent at T. If $\angle ABP = 35^{\circ}$, then find the measure of $\angle PTA$.
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(b) $\angle BPO = \angle OBP = 35^{\circ}$, $\therefore \angle BOP = 110^{\circ}$ (1 Mark)
$\angle OPT = 90^{\circ}$ $\therefore \angle PTA = 20^{\circ}$ (1 Mark)
(b) $\angle BPO = \angle OBP = 35^{\circ}$, $\therefore \angle BOP = 110^{\circ}$ (1 Mark)
$\angle OPT = 90^{\circ}$ $\therefore \angle PTA = 20^{\circ}$ (1 Mark)