63
In the given figure, PA and PB are tangents to a circle centred at O. If $\angle AOB = 130^\circ$, then $\angle APB$ is equal to :
- (a)$130^\circ$
- (b)$50^\circ$
- (c)$120^\circ$
- (d)$90^\circ$
Show SolutionHide Solution↓
(B) $50^\circ$ (1 Mark)
In the given figure, PA and PB are tangents to a circle centred at O. If ∠ AOB = 130° , then ∠ APB is equal to :
CBSE Class 10 Maths PYQ · Circles · Find angles · 1 Mark · March 2026 · Standard
Solve it yourself first — then press ↓ or tap Show Solution. Use ← → for previous / next question.