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If $TP$ and $TQ$ are two tangents to a circle with centre $O$ from an external point $T$ so that $\angle POQ = 120^\circ$, then $\angle PTQ$ is equal to :
- (a)$60^\circ$
- (b)$70^\circ$
- (c)$80^\circ$
- (d)$90^\circ$
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(a) $60^\circ$ (1 Mark)