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A quadrilateral circumscribes the circle as shown in the given figure. If $AB = 5\text{ cm}$, $BC = 7\text{ cm}$ and $CD = 6\text{ cm}$, then find the length of $AD$.
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Solution: Proving $AB + CD = BC + AD$
$5 + 6 = 7 + AD$
$\Rightarrow AD = 4\text{ cm}$
$5 + 6 = 7 + AD$
$\Rightarrow AD = 4\text{ cm}$