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A person is standing at $P$ outside a circular ground at a distance of $26$ m from the centre of the ground. He found that his distances from the points $A$ and $B$ on the ground are $10$ m ($PA$ and $PB$ are tangents to the circle). Find the radius of the circular ground.
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$\angle OAP = 90^\circ$. In right $\Delta OAP, (26)^2 = OA^2 + (10)^2 \implies OA = \sqrt{576} = 24$. $\therefore \text{radius} = 24$ m.