16
The common difference of the A.P.
$\frac{1-4x}{2x}$, $\frac{1-4x}{2x}$, $\frac{1-8x}{2x}$ .......is :
$\frac{1-4x}{2x}$, $\frac{1-4x}{2x}$, $\frac{1-8x}{2x}$ .......is :
- (a)$-2x$
- (b)$2$
- (c)$-2$
- (d)$2x$
Show SolutionHide Solution↓
Sol.
(B) $-2$
(B) $-2$