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If $k + 2$, $4k - 6$ and $3k - 2$ are three consecutive terms of an A.P., then the value of $k$ is :
- (a)$3$
- (b)$-3$
- (c)$4$
- (d)$-4$
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(a) $3$
If k + 2 , 4k - 6 and 3k - 2 are three consecutive terms of an A.P., then the value of k is :
CBSE Class 10 Maths PYQ · Arithmetic Progressions · Basics of AP, CD, Make, find x · 1 Mark · March 2023 · Standard
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