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How many terms are there in an A.P. whose first and fifth terms are $-14$ and $2$, respectively and the last term is $62$.
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Sol. $a = -14, a_5 = 2 \Rightarrow a+4d=2$
$-14 + 4d = 2 \Rightarrow d = 4$
$a_n = 62 \Rightarrow a + (n-1)d = 62$
$-14 + (n - 1)4 = 62 \Rightarrow n = 20$
$-14 + 4d = 2 \Rightarrow d = 4$
$a_n = 62 \Rightarrow a + (n-1)d = 62$
$-14 + (n - 1)4 = 62 \Rightarrow n = 20$