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In the given figure, the shape of the top of a table is that of a sector of a circle with centre O and $\angle AOB = 90^\circ$. If AO = OB = $42$ cm, then find the perimeter of the top of the table.
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Reflex $\angle AOB = 360^\circ - 90^\circ = 270^\circ$
Perimeter of the top of table = length of major arc + $2 \times$ radius
$= \frac{270}{360} \times 2 \times \frac{22}{7} \times 42 + 2 \times 42$
$= 282$ cm
Perimeter of the top of table = length of major arc + $2 \times$ radius
$= \frac{270}{360} \times 2 \times \frac{22}{7} \times 42 + 2 \times 42$
$= 282$ cm