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In the given figure, ABCD is a trapezium with AB $||$ DC. Find the area of the shaded region. (Keep the answer in terms of $\pi$).
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ABCD is a trapezium.
$\therefore \angle A = 120^{\circ}$ and $\angle C = 60^{\circ}$
Area of shaded region = $\frac{120}{360} \times \pi \times (3)^2 + \frac{60}{360} \times \pi \times (6)^2$
$= 9 \pi \text{ cm}^2$
$\therefore \angle A = 120^{\circ}$ and $\angle C = 60^{\circ}$
Area of shaded region = $\frac{120}{360} \times \pi \times (3)^2 + \frac{60}{360} \times \pi \times (6)^2$
$= 9 \pi \text{ cm}^2$