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From a circular sheet of radius $10 \text{ cm}$, a quadrant is cut. Find the perimeter of the remaining sheet.
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Solution: Perimeter of the remaining sheet
$= 2\pi r - \frac{1}{4} \times 2\pi r + 2r = \frac{3}{2}\pi r + 2r$
$= \frac{3}{2} \times \frac{22}{7} \times 10 + 20$
$= \frac{470}{7} \text{ cm}$ or $67.14 \text{ cm}$
$= 2\pi r - \frac{1}{4} \times 2\pi r + 2r = \frac{3}{2}\pi r + 2r$
$= \frac{3}{2} \times \frac{22}{7} \times 10 + 20$
$= \frac{470}{7} \text{ cm}$ or $67.14 \text{ cm}$