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Find the area of the minor and the major sectors of a circle with radius $6$ cm, if the angle subtended by the minor arc at the centre is $60^\circ$. (Use $\pi = 3.14$)
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Area of minor sector $= \frac{3.14 \times(6)^2\times 60^\circ}{360^\circ}$
$= 18.84$
Hence, area of minor sector is $18.84$ cm$^2$
Area of major sector = Area of circle $-$ Area of minor sector
$= 3.14 \times (6)^2 - 18.84$
$= 94.2$
Hence, area of major sector is $94.2$ cm$^2$
$= 18.84$
Hence, area of minor sector is $18.84$ cm$^2$
Area of major sector = Area of circle $-$ Area of minor sector
$= 3.14 \times (6)^2 - 18.84$
$= 94.2$
Hence, area of major sector is $94.2$ cm$^2$