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An arc of a circle of radius $10 \text{ cm}$ subtends a right angle at the centre of the circle. Find the area of the corresponding major sector. (Use $\pi = 3.14$)
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Area of circle = $3.14 \times 10 \times 10 = 314 \text{ cm}^2$
Area of minor sector = $\frac{3.14 \times 10 \times 10 \times 90}{360} = \frac{157}{2} \text{ cm}^2 \text{ or } 78.5 \text{ cm}^2$
Area of major sector = $314 - 78.5 = 235.5 \text{ cm}^2$
Area of minor sector = $\frac{3.14 \times 10 \times 10 \times 90}{360} = \frac{157}{2} \text{ cm}^2 \text{ or } 78.5 \text{ cm}^2$
Area of major sector = $314 - 78.5 = 235.5 \text{ cm}^2$