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A circle of radius $12$ cm is divided into $11$ identical sectors. Find the total area of $7$ such sectors.
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Solution: Central angle of each sector = $(\frac{360}{11})^\circ$ (1 Mark)
Area of $1$ sector = $\frac{360}{11} \times \frac{22}{360} \times 12 \times 12$ (1 Mark)
Area of $7$ sectors = $7 \times \frac{360}{11} \times \frac{22}{360} \times 12 \times 12 = 288$ cm$^2$ (1 Mark)
Area of $1$ sector = $\frac{360}{11} \times \frac{22}{360} \times 12 \times 12$ (1 Mark)
Area of $7$ sectors = $7 \times \frac{360}{11} \times \frac{22}{360} \times 12 \times 12 = 288$ cm$^2$ (1 Mark)