41
A chord of a circle of radius $14\text{ cm}$ subtends an angle of $90^\circ$ at the centre. Find perimeter of shaded region. (Use $\sqrt{2} = 1.41$)
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Solution: In $\Delta AOB, AB = \sqrt{14^2 + 14^2} = 14 \times 1.41 = 19.74\text{ cm}$
Length of the arc $AB = \frac{90}{360} \times 2 \times \frac{22}{7} \times 14 = 22\text{ cm}$
Perimeter of shaded region $= 41.74\text{ cm}$
Length of the arc $AB = \frac{90}{360} \times 2 \times \frac{22}{7} \times 14 = 22\text{ cm}$
Perimeter of shaded region $= 41.74\text{ cm}$