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From a point on the ground, which is $30 \text{ m}$ away from the foot of a vertical tower, the angle of elevation of the top of the tower is found to be $60^\circ$. The height (in metres) of the tower is:
- (a)$10\sqrt{3}$
- (b)$30\sqrt{3}$
- (c)$60$
- (d)$30$
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(B) $30\sqrt{3}$