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When zinc reacts with $\ce{NaOH}$, the product formed is :
- (a)$\ce{Na2O}$
- (b)$\ce{ZnO}$
- (c)$\ce{Na2ZnO2}$
- (d)$\ce{Zn(OH)2}$
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(C)/ $\ce{Na2ZnO2}$
When zinc reacts with NaOH , the product formed is :
CBSE Class 10 Science PYQ · Acids, Bases and Salts · Reactions of acids and bases (with metals, carbonates, metal oxides; neutralisation) · 1 Mark · March 2026 · Standard
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