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To a small amount of copper oxide in a beaker, when we add dilute hydrochloric acid slowly with stirring, the change in the colour of the solution is due to the formation of :
- (a)Copper(II) oxide, which is black in colour.
- (b)Copper(I) chloride, which is blue in colour.
- (c)Copper(II) chloride, which is blue-green in colour.
- (d)Copper(I) oxide, which is black in colour.
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(C)/ Copper (II) chloride, which is blue-green in colour.